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0=-16x^2+18x+10
We move all terms to the left:
0-(-16x^2+18x+10)=0
We add all the numbers together, and all the variables
-(-16x^2+18x+10)=0
We get rid of parentheses
16x^2-18x-10=0
a = 16; b = -18; c = -10;
Δ = b2-4ac
Δ = -182-4·16·(-10)
Δ = 964
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{964}=\sqrt{4*241}=\sqrt{4}*\sqrt{241}=2\sqrt{241}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-18)-2\sqrt{241}}{2*16}=\frac{18-2\sqrt{241}}{32} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-18)+2\sqrt{241}}{2*16}=\frac{18+2\sqrt{241}}{32} $
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